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9x^2-131x+450=0
a = 9; b = -131; c = +450;
Δ = b2-4ac
Δ = -1312-4·9·450
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-131)-31}{2*9}=\frac{100}{18} =5+5/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-131)+31}{2*9}=\frac{162}{18} =9 $
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